What happens when Vitamin C is added to an iodine and starch solution?
Posted by admin on Nov 2, 2009
It’s a grade 10 high school chemistry question 
As you may already know, an iodine and starch solution is an aqueous solution with a dark violet/black color. But when you add vitamin C to the solution, what happens? Can you provide a lengthy explanation for me? Tomorrow, I’m doing an experiment which tests the levels of vitamin C in different substances, but all I need to know for now is what will happen.
Vitamin C. reacts with iodine:
C6H8O6 + I2 ==> C6H6O6 + 2H+ + 2 I-
So you can use titration with iodine to find out the concentration of vitamin C. Since the reaction ratio is 1:1, moles vitamin = moles I2 at the endpoint, so concentrations (M) x volumes are also equal. The reasoning is a bit like in acid-base titrations, which you might have met.
The suspended starch forms a dark blue loosely held complex (almost a solid state solution) with I2, so long as there is any, so it acts as an indicator.
Vitamin C. reacts with iodine:
C6H8O6 + I2 ==> C6H6O6 + 2H+ + 2 I-
So you can use titration with iodine to find out the concentration of vitamin C. Since the reaction ratio is 1:1, moles vitamin = moles I2 at the endpoint, so concentrations (M) x volumes are also equal. The reasoning is a bit like in acid-base titrations, which you might have met.
The suspended starch forms a dark blue loosely held complex (almost a solid state solution) with I2, so long as there is any, so it acts as an indicator.
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